सोडोवचें (V_{1}-V_{2})x(V_{1}+v_{2})=2v_{1}xv_{2}

$$( V _ { 1 } - V _ { 2 } ) x ( V _ { 1 } + v _ { 2 } ) = 2 v _ { 1 } x v _ { 2 }$$

V_2 खातीर सोडोवचें (जटील सोल्यूशन)

$$\left\{\begin{matrix}V_{2}=\frac{V_{1}^{2}+V_{1}v_{2}-2v_{1}v_{2}}{v_{2}+V_{1}}\text{, }&V_{1}\neq -v_{2}\\V_{2}\in \mathrm{C}\text{, }&\left(v_{1}=0\text{ and }V_{1}=-v_{2}\right)\text{ or }\left(v_{2}=0\text{ and }V_{1}=0\right)\text{ or }x=0\end{matrix}\right.$$

लिनियर समिकरण सोडोवंक पांवडे

x न V_{1}-V_{2} गुणपाक विभाजक विशमाचो वापर करचो.

$$\left(V_{1}x-V_{2}x\right)\left(V_{1}+v_{2}\right)=2v_{1}xv_{2}$$

V_{1}+v_{2} न V_{1}x-V_{2}x गुणपाक विभाजक विशमाचो वापर करचो.

$$xV_{1}^{2}+V_{1}xv_{2}-V_{2}xV_{1}-V_{2}xv_{2}=2v_{1}xv_{2}$$

दोनूय कुशींतल्यान xV_{1}^{2} वजा करचें.

$$V_{1}xv_{2}-V_{2}xV_{1}-V_{2}xv_{2}=2v_{1}xv_{2}-xV_{1}^{2}$$

दोनूय कुशींतल्यान V_{1}xv_{2} वजा करचें.

$$-V_{2}xV_{1}-V_{2}xv_{2}=2v_{1}xv_{2}-xV_{1}^{2}-V_{1}xv_{2}$$

संज्ञा परत क्रमान लावची.

$$-V_{1}V_{2}x-V_{2}v_{2}x=2v_{1}v_{2}x-V_{1}v_{2}x-xV_{1}^{2}$$

V_{2} आसपी सगळ्यो संज्ञा एकठांय करच्यो.

$$\left(-V_{1}x-v_{2}x\right)V_{2}=2v_{1}v_{2}x-V_{1}v_{2}x-xV_{1}^{2}$$

समिकरण प्रमाणिक स्वरूपांत आसा.

$$\left(-V_{1}x-v_{2}x\right)V_{2}=2v_{1}v_{2}x-xV_{1}^{2}-V_{1}v_{2}x$$

दोनुय कुशींक -V_{1}x-v_{2}x न भाग लावचो.

$$\frac{\left(-V_{1}x-v_{2}x\right)V_{2}}{-V_{1}x-v_{2}x}=\frac{x\left(-V_{1}v_{2}+2v_{1}v_{2}-V_{1}^{2}\right)}{-V_{1}x-v_{2}x}$$

-V_{1}x-v_{2}x वरवीं भागाकार केल्यार -V_{1}x-v_{2}x वरवीं केल्लो गुणाकार काडटा.

$$V_{2}=\frac{x\left(-V_{1}v_{2}+2v_{1}v_{2}-V_{1}^{2}\right)}{-V_{1}x-v_{2}x}$$

-V_{1}x-v_{2}x नx\left(2v_{1}v_{2}-V_{1}v_{2}-V_{1}^{2}\right) क भाग लावचो.

$$V_{2}=-\frac{2v_{1}v_{2}-V_{1}v_{2}-V_{1}^{2}}{v_{2}+V_{1}}$$

V_2 खातीर सोडोवचें

$$\left\{\begin{matrix}V_{2}=\frac{V_{1}^{2}+V_{1}v_{2}-2v_{1}v_{2}}{v_{2}+V_{1}}\text{, }&V_{1}\neq -v_{2}\\V_{2}\in \mathrm{R}\text{, }&\left(v_{1}=0\text{ and }V_{1}=-v_{2}\right)\text{ or }\left(v_{2}=0\text{ and }V_{1}=0\right)\text{ or }x=0\end{matrix}\right.$$

लिनियर समिकरण सोडोवंक पांवडे

x न V_{1}-V_{2} गुणपाक विभाजक विशमाचो वापर करचो.

$$\left(V_{1}x-V_{2}x\right)\left(V_{1}+v_{2}\right)=2v_{1}xv_{2}$$

V_{1}+v_{2} न V_{1}x-V_{2}x गुणपाक विभाजक विशमाचो वापर करचो.

$$xV_{1}^{2}+V_{1}xv_{2}-V_{2}xV_{1}-V_{2}xv_{2}=2v_{1}xv_{2}$$

दोनूय कुशींतल्यान xV_{1}^{2} वजा करचें.

$$V_{1}xv_{2}-V_{2}xV_{1}-V_{2}xv_{2}=2v_{1}xv_{2}-xV_{1}^{2}$$

दोनूय कुशींतल्यान V_{1}xv_{2} वजा करचें.

$$-V_{2}xV_{1}-V_{2}xv_{2}=2v_{1}xv_{2}-xV_{1}^{2}-V_{1}xv_{2}$$

संज्ञा परत क्रमान लावची.

$$-V_{1}V_{2}x-V_{2}v_{2}x=2v_{1}v_{2}x-V_{1}v_{2}x-xV_{1}^{2}$$

V_{2} आसपी सगळ्यो संज्ञा एकठांय करच्यो.

$$\left(-V_{1}x-v_{2}x\right)V_{2}=2v_{1}v_{2}x-V_{1}v_{2}x-xV_{1}^{2}$$

समिकरण प्रमाणिक स्वरूपांत आसा.

$$\left(-V_{1}x-v_{2}x\right)V_{2}=2v_{1}v_{2}x-xV_{1}^{2}-V_{1}v_{2}x$$

दोनुय कुशींक -V_{1}x-v_{2}x न भाग लावचो.

$$\frac{\left(-V_{1}x-v_{2}x\right)V_{2}}{-V_{1}x-v_{2}x}=\frac{x\left(-V_{1}v_{2}+2v_{1}v_{2}-V_{1}^{2}\right)}{-V_{1}x-v_{2}x}$$

-V_{1}x-v_{2}x वरवीं भागाकार केल्यार -V_{1}x-v_{2}x वरवीं केल्लो गुणाकार काडटा.

$$V_{2}=\frac{x\left(-V_{1}v_{2}+2v_{1}v_{2}-V_{1}^{2}\right)}{-V_{1}x-v_{2}x}$$

-V_{1}x-v_{2}x नx\left(2v_{1}v_{2}-V_{1}v_{2}-V_{1}^{2}\right) क भाग लावचो.

$$V_{2}=-\frac{2v_{1}v_{2}-V_{1}v_{2}-V_{1}^{2}}{v_{2}+V_{1}}$$

V_1 खातीर सोडोवचें (जटील सोल्यूशन)

$$\left\{\begin{matrix}\\V_{1}=\frac{\sqrt{8v_{1}v_{2}+v_{2}^{2}+2V_{2}v_{2}+V_{2}^{2}}+V_{2}-v_{2}}{2}\text{; }V_{1}=\frac{-\sqrt{8v_{1}v_{2}+v_{2}^{2}+2V_{2}v_{2}+V_{2}^{2}}+V_{2}-v_{2}}{2}\text{, }&\text{unconditionally}\\V_{1}\in \mathrm{C}\text{, }&x=0\end{matrix}\right.$$

V_1 खातीर सोडोवचें

$$\left\{\begin{matrix}V_{1}=\frac{\sqrt{8v_{1}v_{2}+v_{2}^{2}+2V_{2}v_{2}+V_{2}^{2}}+V_{2}-v_{2}}{2}\text{; }V_{1}=\frac{-\sqrt{8v_{1}v_{2}+v_{2}^{2}+2V_{2}v_{2}+V_{2}^{2}}+V_{2}-v_{2}}{2}\text{, }&\left(v_{1}>0\text{ and }v_{2}>0\right)\text{ or }\left(v_{2}<0\text{ and }v_{1}<0\right)\text{ or }V_{2}\geq 2\sqrt{-2v_{1}v_{2}}-v_{2}\text{ or }V_{2}\leq -2\sqrt{-2v_{1}v_{2}}-v_{2}\text{ or }\left(v_{2}\leq 0\text{ and }v_{1}\leq 0\right)\text{ or }\left(v_{1}\geq 0\text{ and }v_{2}\geq 0\right)\\V_{1}\in \mathrm{R}\text{, }&x=0\end{matrix}\right.$$