सोडोवचें sigma_x^2=(-2-0)^2*4/9+(0*0)^2*3/9+(1*9)^2*2/9

$$\sigma _ { x } ^ { 2 } = ( - 2 - 0 ) ^ { 2 } \times \frac { 4 } { 9 } + ( 0 \times 0 ) ^ { 2 } \times \frac { 3 } { 9 } + ( 1 \times 9 ) ^ { 2 } \times \frac { 2 } { 9 }$$

σ_x खातीर सोडोवचें

$$\sigma _{x}=\frac{\sqrt{178}}{3}\approx 4.447221355$$

$$\sigma _{x}=-\frac{\sqrt{178}}{3}\approx -4.447221355$$

वर्ग मूळ सोदून पांवडे

-2 मेळोवंक -2 आनी 0 वजा करचे.

$$\sigma _{x}^{2}=\left(-2\right)^{2}\times \frac{4}{9}+\left(0\times 0\right)^{2}\times \frac{3}{9}+\left(1\times 9\right)^{2}\times \frac{2}{9}$$

4 मेळोवंक 2 चो -2 पॉवर मेजचो.

$$\sigma _{x}^{2}=4\times \frac{4}{9}+\left(0\times 0\right)^{2}\times \frac{3}{9}+\left(1\times 9\right)^{2}\times \frac{2}{9}$$

\frac{16}{9} मेळोवंक 4 आनी \frac{4}{9} गुणचें.

$$\sigma _{x}^{2}=\frac{16}{9}+\left(0\times 0\right)^{2}\times \frac{3}{9}+\left(1\times 9\right)^{2}\times \frac{2}{9}$$

0 मेळोवंक 0 आनी 0 गुणचें.

$$\sigma _{x}^{2}=\frac{16}{9}+0^{2}\times \frac{3}{9}+\left(1\times 9\right)^{2}\times \frac{2}{9}$$

0 मेळोवंक 2 चो 0 पॉवर मेजचो.

$$\sigma _{x}^{2}=\frac{16}{9}+0\times \frac{3}{9}+\left(1\times 9\right)^{2}\times \frac{2}{9}$$

3 भायर काडून आनी रद्द करून एकदम उण्या संज्ञेत अपुर्णांक \frac{3}{9} उणो करचो.

$$\sigma _{x}^{2}=\frac{16}{9}+0\times \frac{1}{3}+\left(1\times 9\right)^{2}\times \frac{2}{9}$$

0 मेळोवंक 0 आनी \frac{1}{3} गुणचें.

$$\sigma _{x}^{2}=\frac{16}{9}+0+\left(1\times 9\right)^{2}\times \frac{2}{9}$$

\frac{16}{9} मेळोवंक \frac{16}{9} आनी 0 ची बेरीज करची.

$$\sigma _{x}^{2}=\frac{16}{9}+\left(1\times 9\right)^{2}\times \frac{2}{9}$$

9 मेळोवंक 1 आनी 9 गुणचें.

$$\sigma _{x}^{2}=\frac{16}{9}+9^{2}\times \frac{2}{9}$$

81 मेळोवंक 2 चो 9 पॉवर मेजचो.

$$\sigma _{x}^{2}=\frac{16}{9}+81\times \frac{2}{9}$$

18 मेळोवंक 81 आनी \frac{2}{9} गुणचें.

$$\sigma _{x}^{2}=\frac{16}{9}+18$$

\frac{178}{9} मेळोवंक \frac{16}{9} आनी 18 ची बेरीज करची.

$$\sigma _{x}^{2}=\frac{178}{9}$$

समिकरणाच्या दोनूय कुशींनी वर्गमूळ काडचो.

$$\sigma _{x}=\frac{\sqrt{178}}{3} \sigma _{x}=-\frac{\sqrt{178}}{3}$$

क्वॉड्रेटिक सिध्दांत वापरून पांवडे

-2 मेळोवंक -2 आनी 0 वजा करचे.

$$\sigma _{x}^{2}=\left(-2\right)^{2}\times \frac{4}{9}+\left(0\times 0\right)^{2}\times \frac{3}{9}+\left(1\times 9\right)^{2}\times \frac{2}{9}$$

4 मेळोवंक 2 चो -2 पॉवर मेजचो.

$$\sigma _{x}^{2}=4\times \frac{4}{9}+\left(0\times 0\right)^{2}\times \frac{3}{9}+\left(1\times 9\right)^{2}\times \frac{2}{9}$$

\frac{16}{9} मेळोवंक 4 आनी \frac{4}{9} गुणचें.

$$\sigma _{x}^{2}=\frac{16}{9}+\left(0\times 0\right)^{2}\times \frac{3}{9}+\left(1\times 9\right)^{2}\times \frac{2}{9}$$

0 मेळोवंक 0 आनी 0 गुणचें.

$$\sigma _{x}^{2}=\frac{16}{9}+0^{2}\times \frac{3}{9}+\left(1\times 9\right)^{2}\times \frac{2}{9}$$

0 मेळोवंक 2 चो 0 पॉवर मेजचो.

$$\sigma _{x}^{2}=\frac{16}{9}+0\times \frac{3}{9}+\left(1\times 9\right)^{2}\times \frac{2}{9}$$

3 भायर काडून आनी रद्द करून एकदम उण्या संज्ञेत अपुर्णांक \frac{3}{9} उणो करचो.

$$\sigma _{x}^{2}=\frac{16}{9}+0\times \frac{1}{3}+\left(1\times 9\right)^{2}\times \frac{2}{9}$$

0 मेळोवंक 0 आनी \frac{1}{3} गुणचें.

$$\sigma _{x}^{2}=\frac{16}{9}+0+\left(1\times 9\right)^{2}\times \frac{2}{9}$$

\frac{16}{9} मेळोवंक \frac{16}{9} आनी 0 ची बेरीज करची.

$$\sigma _{x}^{2}=\frac{16}{9}+\left(1\times 9\right)^{2}\times \frac{2}{9}$$

9 मेळोवंक 1 आनी 9 गुणचें.

$$\sigma _{x}^{2}=\frac{16}{9}+9^{2}\times \frac{2}{9}$$

81 मेळोवंक 2 चो 9 पॉवर मेजचो.

$$\sigma _{x}^{2}=\frac{16}{9}+81\times \frac{2}{9}$$

18 मेळोवंक 81 आनी \frac{2}{9} गुणचें.

$$\sigma _{x}^{2}=\frac{16}{9}+18$$

\frac{178}{9} मेळोवंक \frac{16}{9} आनी 18 ची बेरीज करची.

$$\sigma _{x}^{2}=\frac{178}{9}$$

दोनूय कुशींतल्यान \frac{178}{9} वजा करचें.

$$\sigma _{x}^{2}-\frac{178}{9}=0$$

हें समिकरण प्रमाणित पद्दतीन आसा: ax^{2}+bx+c=0. क्वॉड्रेटिक सिध्दांत \frac{-b±\sqrt{b^{2}-4ac}}{2a} त a खातीर 1, b खातीर 0 आनी c खातीर -\frac{178}{9} बदली घेवचे.

$$\sigma _{x}=\frac{0±\sqrt{0^{2}-4\left(-\frac{178}{9}\right)}}{2}$$

0 वर्गमूळ.

$$\sigma _{x}=\frac{0±\sqrt{-4\left(-\frac{178}{9}\right)}}{2}$$

-\frac{178}{9}क -4 फावटी गुणचें.

$$\sigma _{x}=\frac{0±\sqrt{\frac{712}{9}}}{2}$$

\frac{712}{9} चें वर्गमूळ घेवचें.

$$\sigma _{x}=\frac{0±\frac{2\sqrt{178}}{3}}{2}$$

जेन्ना ± अदीक आस्ता तेन्ना समिकरण \sigma _{x}=\frac{0±\frac{2\sqrt{178}}{3}}{2} सोडोवचें.

$$\sigma _{x}=\frac{\sqrt{178}}{3}$$

जेन्ना ± वजा आस्ता तेन्ना समिकरण \sigma _{x}=\frac{0±\frac{2\sqrt{178}}{3}}{2} सोडोवचें.

$$\sigma _{x}=-\frac{\sqrt{178}}{3}$$

समिकरण आतां सुटावें जालें.

$$\sigma _{x}=\frac{\sqrt{178}}{3} \sigma _{x}=-\frac{\sqrt{178}}{3}$$