सोडोवचें -2x+3/x-1leq0

$$\frac{ -2x+3 }{ x-1 } \leq 0$$

x खातीर सोडोवचें

$$x\in (-\infty,1)\cup [\frac{3}{2},\infty)$$

सोडोवणी पांवडे

For the quotient to be ≤0, one of the values 3-2x and x-1 has to be ≥0, the other has to be ≤0, and x-1 cannot be zero. Consider the case when 3-2x\geq 0 and x-1 is negative.

$$3-2x\geq 0 x-1<0$$

दोनूय असमानतायांचें समाधान करपी उत्तर x<1 आसा.

$$x<1$$

Consider the case when 3-2x\leq 0 and x-1 is positive.

$$3-2x\leq 0 x-1>0$$

दोनूय असमानतायांचें समाधान करपी उत्तर x\geq \frac{3}{2} आसा.

$$x\geq \frac{3}{2}$$

प्राप्त समाधानाचें संयुक्त हें निमाणें समाधान आसा.

$$x<1\text{; }x\geq \frac{3}{2}$$