सोडोवचें x^2/x^2+6x+9-4/x^2-9=

$$\frac { x ^ { 2 } } { x ^ { 2 } + 6 x + 9 } - \frac { 4 } { x ^ { 2 } - 9 } =$$

मूल्यांकन करचें

$$\frac{x^{3}-3x^{2}-4x-12}{\left(x-3\right)\left(x+3\right)^{2}}$$

संक्षिप्त समाधान पांवडे

x^{2}+6x+9 गुणकपद काडचें. x^{2}-9 गुणकपद काडचें.

$$\frac{x^{2}}{\left(x+3\right)^{2}}-\frac{4}{\left(x-3\right)\left(x+3\right)}$$

ऍक्सप्रेशन जमा करूंक वा वजा करूंक, तांचे डिनोमिनेटर तसोच दवरूंक विस्तारावचें. \left(x+3\right)^{2} आनी \left(x-3\right)\left(x+3\right) चो किमान सामान्य गुणाकार आसा \left(x-3\right)\left(x+3\right)^{2}. \frac{x-3}{x-3}क \frac{x^{2}}{\left(x+3\right)^{2}} फावटी गुणचें. \frac{x+3}{x+3}क \frac{4}{\left(x-3\right)\left(x+3\right)} फावटी गुणचें.

$$\frac{x^{2}\left(x-3\right)}{\left(x-3\right)\left(x+3\right)^{2}}-\frac{4\left(x+3\right)}{\left(x-3\right)\left(x+3\right)^{2}}$$

\frac{x^{2}\left(x-3\right)}{\left(x-3\right)\left(x+3\right)^{2}} आनी \frac{4\left(x+3\right)}{\left(x-3\right)\left(x+3\right)^{2}} चे समान डिनोमिनेटर आशिल्ल्यान, तांचे न्युमरेटर वजा करून तांची वजाबाकी करची.

$$\frac{x^{2}\left(x-3\right)-4\left(x+3\right)}{\left(x-3\right)\left(x+3\right)^{2}}$$

x^{2}\left(x-3\right)-4\left(x+3\right) त गुणाकार करचे.

$$\frac{x^{3}-3x^{2}-4x-12}{\left(x-3\right)\left(x+3\right)^{2}}$$

\left(x-3\right)\left(x+3\right)^{2} विस्तारीत करचो.

$$\frac{x^{3}-3x^{2}-4x-12}{x^{3}+3x^{2}-9x-27}$$

w.r.t. x चो फरक काडचो

$$\frac{2x\left(3x^{2}-14x+39\right)}{\left(x-3\right)^{2}\left(x+3\right)^{3}}$$