सोडोवचें frac{R_{1}}{2R_{1}-R}-frac{R_{1}}{2R_{1}+R}

$$\frac { R _ { 1 } } { 2 R _ { 1 } - R } - \frac { R _ { 1 } } { 2 R _ { 1 } + R }$$

मूल्यांकन करचें

$$\frac{2RR_{1}}{4R_{1}^{2}-R^{2}}$$

संक्षिप्त समाधान पांवडे

ऍक्सप्रेशन जमा करूंक वा वजा करूंक, तांचे डिनोमिनेटर तसोच दवरूंक विस्तारावचें. 2R_{1}-R आनी 2R_{1}+R चो किमान सामान्य गुणाकार आसा \left(R+2R_{1}\right)\left(-R+2R_{1}\right). \frac{R+2R_{1}}{R+2R_{1}}क \frac{R_{1}}{2R_{1}-R} फावटी गुणचें. \frac{-R+2R_{1}}{-R+2R_{1}}क \frac{R_{1}}{2R_{1}+R} फावटी गुणचें.

$$\frac{R_{1}\left(R+2R_{1}\right)}{\left(R+2R_{1}\right)\left(-R+2R_{1}\right)}-\frac{R_{1}\left(-R+2R_{1}\right)}{\left(R+2R_{1}\right)\left(-R+2R_{1}\right)}$$

\frac{R_{1}\left(R+2R_{1}\right)}{\left(R+2R_{1}\right)\left(-R+2R_{1}\right)} आनी \frac{R_{1}\left(-R+2R_{1}\right)}{\left(R+2R_{1}\right)\left(-R+2R_{1}\right)} चे समान डिनोमिनेटर आशिल्ल्यान, तांचे न्युमरेटर वजा करून तांची वजाबाकी करची.

$$\frac{R_{1}\left(R+2R_{1}\right)-R_{1}\left(-R+2R_{1}\right)}{\left(R+2R_{1}\right)\left(-R+2R_{1}\right)}$$

R_{1}\left(R+2R_{1}\right)-R_{1}\left(-R+2R_{1}\right) त गुणाकार करचे.

$$\frac{R_{1}R+2R_{1}^{2}+R_{1}R-2R_{1}^{2}}{\left(R+2R_{1}\right)\left(-R+2R_{1}\right)}$$

R_{1}R+2R_{1}^{2}+R_{1}R-2R_{1}^{2} त समान शब्द एकठांय करचे.

$$\frac{2R_{1}R}{\left(R+2R_{1}\right)\left(-R+2R_{1}\right)}$$

\left(R+2R_{1}\right)\left(-R+2R_{1}\right) विस्तारीत करचो.

$$\frac{2R_{1}R}{-R^{2}+4R_{1}^{2}}$$

गुणकपद

$$\frac{2RR_{1}}{4R_{1}^{2}-R^{2}}$$