सोडोवचें 2/x^2+7x+10+3/x^2-25

$$\frac { 2 } { x ^ { 2 } + 7 x + 10 } + \frac { 3 } { x ^ { 2 } - 25 }$$

मूल्यांकन करचें

$$\frac{5x-4}{\left(x+2\right)\left(x^{2}-25\right)}$$

संक्षिप्त समाधान पांवडे

x^{2}+7x+10 गुणकपद काडचें. x^{2}-25 गुणकपद काडचें.

$$\frac{2}{\left(x+2\right)\left(x+5\right)}+\frac{3}{\left(x-5\right)\left(x+5\right)}$$

ऍक्सप्रेशन जमा करूंक वा वजा करूंक, तांचे डिनोमिनेटर तसोच दवरूंक विस्तारावचें. \left(x+2\right)\left(x+5\right) आनी \left(x-5\right)\left(x+5\right) चो किमान सामान्य गुणाकार आसा \left(x-5\right)\left(x+2\right)\left(x+5\right). \frac{x-5}{x-5}क \frac{2}{\left(x+2\right)\left(x+5\right)} फावटी गुणचें. \frac{x+2}{x+2}क \frac{3}{\left(x-5\right)\left(x+5\right)} फावटी गुणचें.

$$\frac{2\left(x-5\right)}{\left(x-5\right)\left(x+2\right)\left(x+5\right)}+\frac{3\left(x+2\right)}{\left(x-5\right)\left(x+2\right)\left(x+5\right)}$$

\frac{2\left(x-5\right)}{\left(x-5\right)\left(x+2\right)\left(x+5\right)} आनी \frac{3\left(x+2\right)}{\left(x-5\right)\left(x+2\right)\left(x+5\right)} चे समान डिनोमिनेटर आशिल्ल्यान, तांचे न्युमरेटर जो़डून तांची बेरीज करची.

$$\frac{2\left(x-5\right)+3\left(x+2\right)}{\left(x-5\right)\left(x+2\right)\left(x+5\right)}$$

2\left(x-5\right)+3\left(x+2\right) त गुणाकार करचे.

$$\frac{2x-10+3x+6}{\left(x-5\right)\left(x+2\right)\left(x+5\right)}$$

2x-10+3x+6 त समान शब्द एकठांय करचे.

$$\frac{5x-4}{\left(x-5\right)\left(x+2\right)\left(x+5\right)}$$

\left(x-5\right)\left(x+2\right)\left(x+5\right) विस्तारीत करचो.

$$\frac{5x-4}{x^{3}+2x^{2}-25x-50}$$

w.r.t. x चो फरक काडचो

$$\frac{2\left(-5x^{3}+x^{2}+8x-175\right)}{\left(\left(x+2\right)\left(x^{2}-25\right)\right)^{2}}$$