सोडोवचें 8/x+3+12/x+7/frac{5x+23{x^2+10x+21}}

$$\frac { \frac { 8 } { x + 3 } + \frac { 12 } { x + 7 } } { \frac { 5 x + 23 } { x ^ { 2 } + 10 x + 21 } }$$

मूल्यांकन करचें

$$4$$

संक्षिप्त समाधान पांवडे

ऍक्सप्रेशन जमा करूंक वा वजा करूंक, तांचे डिनोमिनेटर तसोच दवरूंक विस्तारावचें. x+3 आनी x+7 चो किमान सामान्य गुणाकार आसा \left(x+3\right)\left(x+7\right). \frac{x+7}{x+7}क \frac{8}{x+3} फावटी गुणचें. \frac{x+3}{x+3}क \frac{12}{x+7} फावटी गुणचें.

$$\frac{\frac{8\left(x+7\right)}{\left(x+3\right)\left(x+7\right)}+\frac{12\left(x+3\right)}{\left(x+3\right)\left(x+7\right)}}{\frac{5x+23}{x^{2}+10x+21}}$$

\frac{8\left(x+7\right)}{\left(x+3\right)\left(x+7\right)} आनी \frac{12\left(x+3\right)}{\left(x+3\right)\left(x+7\right)} चे समान डिनोमिनेटर आशिल्ल्यान, तांचे न्युमरेटर जो़डून तांची बेरीज करची.

$$\frac{\frac{8\left(x+7\right)+12\left(x+3\right)}{\left(x+3\right)\left(x+7\right)}}{\frac{5x+23}{x^{2}+10x+21}}$$

8\left(x+7\right)+12\left(x+3\right) त गुणाकार करचे.

$$\frac{\frac{8x+56+12x+36}{\left(x+3\right)\left(x+7\right)}}{\frac{5x+23}{x^{2}+10x+21}}$$

8x+56+12x+36 त समान शब्द एकठांय करचे.

$$\frac{\frac{20x+92}{\left(x+3\right)\left(x+7\right)}}{\frac{5x+23}{x^{2}+10x+21}}$$

\frac{5x+23}{x^{2}+10x+21} च्या पुरकाक \frac{20x+92}{\left(x+3\right)\left(x+7\right)} गुणून \frac{5x+23}{x^{2}+10x+21} न \frac{20x+92}{\left(x+3\right)\left(x+7\right)} क भाग लावचो.

$$\frac{\left(20x+92\right)\left(x^{2}+10x+21\right)}{\left(x+3\right)\left(x+7\right)\left(5x+23\right)}$$

आदींच फॅक्टर्ड नाशिल्लें ऍक्सप्रेशन फॅक्ट करचें.

$$\frac{4\left(x+3\right)\left(x+7\right)\left(5x+23\right)}{\left(x+3\right)\left(x+7\right)\left(5x+23\right)}$$

न्युमरेटर आनी डिनोमिनेटर अशा दोगांचेरूय \left(x+3\right)\left(x+7\right)\left(5x+23\right) रद्द करचो.

$$4$$

गुणकपद

$$2^{2}$$