다음을 풀어보세요: -2/3+5/3b^3-(-1/6)+1-(-1/7b^3)+frac{1}{2}-(frac{2}{7}b^3-frac{2}{3}b^3)

계산

확장

퀴즈

Polynomial

다음과 비슷한 문제 5개:

비슷한 문제의 웹 검색 결과

https://socratic.org/questions/prove-that-a-2-b-2-c-2bc-b-2-2bc-c-2-a-2-s-b-s-c-s-s-a-if-a-b-c-2s

https://socratic.org/questions/how-do-you-solve-frac-2-3-frac-1-3-frac-1-2-frac-1-2-frac-1-3-frac-1-5-2-frac-2-

https://www.tiger-algebra.com/drill/6a~2-26a-20/a~2-12a_35•2a~2-9a-35/3a~2_20a_1/

https://math.stackexchange.com/questions/2761061/issue-in-the-solution-of-general-cubic-equation

https://math.stackexchange.com/questions/2756964/calculate-the-probability-that-more-than-three-claims-will-be-received-during-a

클립보드에 복사됨

-\frac{2}{3}+\frac{5}{3}b^{3}+\frac{1}{6}+1-\left(-\frac{1}{7}b^{3}\right)+\frac{1}{2}-\left(\frac{2}{7}b^{3}-\frac{2}{3}b^{3}\right)

-\frac{1}{6}의 반대는 \frac{1}{6}입니다.

-\frac{1}{2}+\frac{5}{3}b^{3}+1-\left(-\frac{1}{7}b^{3}\right)+\frac{1}{2}-\left(\frac{2}{7}b^{3}-\frac{2}{3}b^{3}\right)

-\frac{2}{3}과(와) \frac{1}{6}을(를) 더하여 -\frac{1}{2}을(를) 구합니다.

\frac{1}{2}+\frac{5}{3}b^{3}-\left(-\frac{1}{7}b^{3}\right)+\frac{1}{2}-\left(\frac{2}{7}b^{3}-\frac{2}{3}b^{3}\right)

-\frac{1}{2}과(와) 1을(를) 더하여 \frac{1}{2}을(를) 구합니다.

\frac{1}{2}+\frac{5}{3}b^{3}+\frac{1}{7}b^{3}+\frac{1}{2}-\left(\frac{2}{7}b^{3}-\frac{2}{3}b^{3}\right)

-\frac{1}{7}b^{3}의 반대는 \frac{1}{7}b^{3}입니다.

\frac{1}{2}+\frac{38}{21}b^{3}+\frac{1}{2}-\left(\frac{2}{7}b^{3}-\frac{2}{3}b^{3}\right)

\frac{5}{3}b^{3}과(와) \frac{1}{7}b^{3}을(를) 결합하여 \frac{38}{21}b^{3}(을)를 구합니다.

1+\frac{38}{21}b^{3}-\left(\frac{2}{7}b^{3}-\frac{2}{3}b^{3}\right)

\frac{1}{2}과(와) \frac{1}{2}을(를) 더하여 1을(를) 구합니다.

1+\frac{38}{21}b^{3}-\left(-\frac{8}{21}b^{3}\right)

\frac{2}{7}b^{3}과(와) -\frac{2}{3}b^{3}을(를) 결합하여 -\frac{8}{21}b^{3}(을)를 구합니다.

1+\frac{38}{21}b^{3}+\frac{8}{21}b^{3}

-\frac{8}{21}b^{3}의 반대는 \frac{8}{21}b^{3}입니다.

1+\frac{46}{21}b^{3}

\frac{38}{21}b^{3}과(와) \frac{8}{21}b^{3}을(를) 결합하여 \frac{46}{21}b^{3}(을)를 구합니다.