다음을 풀어보세요: {l}{sin3/5quadcosbeta=-5/13}{sin(a+7)=32}

$$\left. \begin{array} { l } { \sin \frac { 3 } { 5 } \quad \cos \beta = - \frac { 5 } { 13 } } \\ { \sin ( a + 7 ) = 32 } \end{array} \right.$$

β, a에 대한 해

$$\beta =\pi +\left(-i\right)\ln(\frac{156250000000000000}{4254162297224853}+\frac{1}{4254162297224853}\times 24395964603148870561481014759128391^{\frac{1}{2}})+2\pi n_{1}\text{, }n_{1}\in \mathrm{Z}\text{, }a=-7+\left(-i\right)\ln(32i+\left(-i\right)\times 1023^{\frac{1}{2}})+2\pi n_{2}\text{, }n_{2}\in \mathrm{Z}$$

$$\beta =\pi +\left(-i\right)\ln(\frac{156250000000000000}{4254162297224853}+\frac{1}{4254162297224853}\times 24395964603148870561481014759128391^{\frac{1}{2}})+2\pi n_{1}\text{, }n_{1}\in \mathrm{Z}\text{, }a=-7+\left(-i\right)\ln(32i+i\times 1023^{\frac{1}{2}})+2\pi n_{4}\text{, }n_{4}\in \mathrm{Z}$$

$$\beta =\pi +\left(-i\right)\ln(\frac{156250000000000000}{4254162297224853}+\left(-\frac{1}{4254162297224853}\right)\times 24395964603148870561481014759128391^{\frac{1}{2}})+2\pi n_{5}\text{, }n_{5}\in \mathrm{Z}\text{, }a=-7+\left(-i\right)\ln(32i+\left(-i\right)\times 1023^{\frac{1}{2}})+2\pi n_{2}\text{, }n_{2}\in \mathrm{Z}$$

$$\beta =\pi +\left(-i\right)\ln(\frac{156250000000000000}{4254162297224853}+\left(-\frac{1}{4254162297224853}\right)\times 24395964603148870561481014759128391^{\frac{1}{2}})+2\pi n_{5}\text{, }n_{5}\in \mathrm{Z}\text{, }a=-7+\left(-i\right)\ln(32i+i\times 1023^{\frac{1}{2}})+2\pi n_{4}\text{, }n_{4}\in \mathrm{Z}$$