다음을 풀어보세요: {l}{sqrt{(4t)^2+{(5t^2)}^2}=3}{u=t}{v=u}{w=v}{x=w}{text{Solvefor}ytext{where}}{y=x}

$$\left. \begin{array} { l } { \sqrt{{(4 t)} ^ {2} + {(5 t ^ {2})} ^ {2}} = 3 }\\ { u = t }\\ { v = u }\\ { w = v }\\ { x = w }\\ { \text{Solve for } y \text{ where} } \\ { y = x } \end{array} \right.$$

t, u, v, w, x, y에 대한 해 (complex solution)

$$x=\frac{3}{5}=0.6\text{, }y=\frac{3}{5}=0.6\text{, }t=\frac{3}{5}=0.6\text{, }u=\frac{3}{5}=0.6\text{, }v=\frac{3}{5}=0.6\text{, }w=\frac{3}{5}=0.6$$

$$x=-i\text{, }y=-i\text{, }t=-i\text{, }u=-i\text{, }v=-i\text{, }w=-i$$

$$x=i\text{, }y=i\text{, }t=i\text{, }u=i\text{, }v=i\text{, }w=i$$

$$x=-\frac{3}{5}=-0.6\text{, }y=-\frac{3}{5}=-0.6\text{, }t=-\frac{3}{5}=-0.6\text{, }u=-\frac{3}{5}=-0.6\text{, }v=-\frac{3}{5}=-0.6\text{, }w=-\frac{3}{5}=-0.6$$

t, u, v, w, x, y에 대한 해

$$x=\frac{3}{5}=0.6\text{, }y=\frac{3}{5}=0.6\text{, }t=\frac{3}{5}=0.6\text{, }u=\frac{3}{5}=0.6\text{, }v=\frac{3}{5}=0.6\text{, }w=\frac{3}{5}=0.6$$

$$x=-\frac{3}{5}=-0.6\text{, }y=-\frac{3}{5}=-0.6\text{, }t=-\frac{3}{5}=-0.6\text{, }u=-\frac{3}{5}=-0.6\text{, }v=-\frac{3}{5}=-0.6\text{, }w=-\frac{3}{5}=-0.6$$