a^3+b^3=(a+b) шешу

$$a ^ { 3 } + b ^ { 3 } = ( a + b )$$

a мәнін табыңыз (complex solution)

$$a=\frac{\sqrt{4-3b^{2}}+b}{2}$$

$$a=\frac{-\sqrt{4-3b^{2}}+b}{2}$$

$$a=-b$$

b мәнін табыңыз (complex solution)

$$b=\frac{\sqrt{4-3a^{2}}+a}{2}$$

$$b=\frac{-\sqrt{4-3a^{2}}+a}{2}$$

$$b=-a$$

a мәнін табыңыз

$$\left\{\begin{matrix}\\a=-b\text{, }&\text{unconditionally}\\a=\frac{\sqrt{4-3b^{2}}+b}{2}\text{; }a=\frac{-\sqrt{4-3b^{2}}+b}{2}\text{, }&|b|\leq \frac{2\sqrt{3}}{3}\end{matrix}\right.$$

b мәнін табыңыз

$$\left\{\begin{matrix}\\b=-a\text{, }&\text{unconditionally}\\b=\frac{\sqrt{4-3a^{2}}+a}{2}\text{; }b=\frac{-\sqrt{4-3a^{2}}+a}{2}\text{, }&|a|\leq \frac{2\sqrt{3}}{3}\end{matrix}\right.$$