E=80^x-3+6^x+1+24/44^x-1-2^x+2 шешу

$$E = \frac { 80 ^ { x - 3 } + 6 ^ { x + 1 } + 24 } { 44 ^ { x - 1 } - 2 ^ { x + 2 } }$$

E мәнін табыңыз (complex solution)

$$\left\{\begin{matrix}E=\frac{11\left(3072000\times 6^{x}+80^{x}[phone]\right)}{128000\left(44^{x}-176\times 2^{x}\right)}\text{, }&128000\times 44^{x}-22528000\times 2^{x}\neq 0\text{ and }44^{x}-176\times 2^{x}\neq 0\text{ and }44^{x-1}-2^{x+2}\neq 0\\E\in \mathrm{C}\text{, }&-11\times 80^{x}-33792000\times 6^{x}-135168000=0\text{ and }128000\times 44^{x}-22528000\times 2^{x}=0\text{ and }44^{x}-176\times 2^{x}\neq 0\text{ and }44^{x-1}-2^{x+2}\neq 0\end{matrix}\right.$$

E мәнін табыңыз

$$E=\frac{11\left(3072000\times 6^{x}+80^{x}[phone]\right)}{128000\times 2^{x}\left(22^{x}-176\right)}$$

$$x\neq \log_{22}\left(176\right)$$