x/frac{x{y}+8}=x/frac{x{y}-8}-12 шешу

$$\frac{ x }{ \frac{ x }{ y } +8 } = \frac{ x }{ \frac{ x }{ y } -8 } -12$$

x мәнін табыңыз (complex solution)

$$x=\frac{2\left(\sqrt{y^{2}\left(y^{2}+144\right)}+y^{2}\right)}{3}$$

$$x=\frac{2\left(-\sqrt{y^{2}\left(y^{2}+144\right)}+y^{2}\right)}{3}\text{, }y\neq 0$$

y мәнін табыңыз (complex solution)

$$y=-\frac{\sqrt{3}\left(x+48\right)^{-\frac{1}{2}}x}{2}$$

$$y=\frac{\sqrt{3}\left(x+48\right)^{-\frac{1}{2}}x}{2}\text{, }x\neq 0\text{ and }x\neq -48$$

x мәнін табыңыз

$$x=\frac{2y\left(\sqrt{y^{2}+144}+y\right)}{3}$$

$$x=\frac{2y\left(-\sqrt{y^{2}+144}+y\right)}{3}\text{, }y\neq 0$$

y мәнін табыңыз

$$y=\frac{\sqrt{\frac{3}{x+48}}x}{2}$$

$$y=-\frac{\sqrt{\frac{3}{x+48}}x}{2}\text{, }x\neq 0\text{ and }x>-48$$