გადაწყვიტეთ x^2-y^3z^4+3-9+1-15=6

$${ x }^{ 2 } - { y }^{ 3 } { z }^{ 4 } +3-9+1-15=6$$

ამოხსნა x-ისთვის (complex solution)

$$x=-\sqrt{y^{3}z^{4}+26}$$

$$x=\sqrt{y^{3}z^{4}+26}$$

ამოხსნა y-ისთვის (complex solution)

$$\left\{\begin{matrix}y=e^{\frac{2\pi i}{3}}z^{-\frac{4}{3}}\sqrt[3]{x^{2}-26}\text{; }y=z^{-\frac{4}{3}}\sqrt[3]{x^{2}-26}\text{; }y=e^{\frac{4\pi i}{3}}z^{-\frac{4}{3}}\sqrt[3]{x^{2}-26}\text{, }&z\neq 0\\y\in \mathrm{C}\text{, }&\left(x=\sqrt{26}\text{ or }x=-\sqrt{26}\right)\text{ and }z=0\end{matrix}\right.$$

ამოხსნა x-ისთვის

$$x=\sqrt{y^{3}z^{4}+26}$$

$$x=-\sqrt{y^{3}z^{4}+26}\text{, }z=0\text{ or }y\geq -\frac{\sqrt[3]{26}}{z^{\frac{4}{3}}}$$

ამოხსნა y-ისთვის

$$\left\{\begin{matrix}y=\frac{\sqrt[3]{x^{2}-26}}{z^{\frac{4}{3}}}\text{, }&z\neq 0\\y\in \mathrm{R}\text{, }&z=0\text{ and }|x|=\sqrt{26}\end{matrix}\right.$$