Risolvi y=8sqrt{x}-2x

$$y = 8 \sqrt { x } - 2 x$$

Trova x (soluzione complessa)

$$\left\{\begin{matrix}x=0\text{, }&y=0\\x=\frac{\left(-\sqrt{16-2y}+4\right)^{2}}{4}\text{, }&arg(-\frac{\sqrt{16-2y}}{2}+2)<\pi \\x=\frac{\left(\sqrt{16-2y}+4\right)^{2}}{4}\text{, }&arg(\frac{\sqrt{16-2y}}{2}+2)<\pi \end{matrix}\right,$$

Trova y (soluzione complessa)

$$y=-2x+8\sqrt{x}$$

Trova x

$$\left\{\begin{matrix}x=\frac{\left(-\sqrt{16-2y}+4\right)^{2}}{4}\text{, }&-\frac{\sqrt{16-2y}}{2}+2\geq 0\text{ and }y\leq 8\\x=\frac{\left(\sqrt{16-2y}+4\right)^{2}}{4}\text{, }&y\leq 8\end{matrix}\right,$$

Trova y

$$y=-2x+8\sqrt{x}$$

$$x\geq 0$$