Leysa a=sqrt{c^2-b^2}

$$a = \sqrt { c ^ { 2 } - b ^ { 2 } }$$

Leystu fyrir b (complex solution)

$$b=-\sqrt{c^{2}-a^{2}}$$

$$b=\sqrt{c^{2}-a^{2}}\text{, }arg(a)<\pi \text{ or }a=0$$

Leystu fyrir a

$$a=\sqrt{c^{2}-b^{2}}$$

$$|c|\geq |b|$$

Leystu fyrir b

$$b=\sqrt{c^{2}-a^{2}}$$

$$b=-\sqrt{c^{2}-a^{2}}\text{, }a\geq 0\text{ and }\left(a=0\text{ or }a<c\text{ or }c\neq 0\right)\text{ and }a\leq |c|$$