Leysa {l}{(x+2)^2+(y-1)^2=1}{z=my}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { {(x + 2)} ^ {2} + {(y - 1)} ^ {2} = 1 }\\ { z = m y }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Leystu fyrir x, y, z (complex solution)

$$\left\{\begin{matrix}x=\frac{i\sqrt{c}\sqrt{c-2m}-2m}{m}\text{, }y=\frac{c}{m}\text{, }z=c\text{; }x=\frac{-i\sqrt{c}\sqrt{c-2m}-2m}{m}\text{, }y=\frac{c}{m}\text{, }z=c\text{, }&b=c\text{ and }m\neq 0\text{ and }a=c\\x\in \mathrm{C}\text{, }y=\sqrt{-\left(x+1\right)\left(x+3\right)}+1\text{, }z=0\text{; }x\in \mathrm{C}\text{, }y=-\sqrt{-\left(x+1\right)\left(x+3\right)}+1\text{, }z=0\text{, }&a=0\text{ and }m=0\text{ and }b=0\text{ and }c=0\end{matrix}\right.$$

Leystu fyrir x, y, z

$$\left\{\begin{matrix}x=-\frac{\sqrt{b\left(2m-b\right)}+2|m|}{|m|}\text{, }y=\frac{b}{m}\text{, }z=b\text{; }x=\frac{\sqrt{b\left(2m-b\right)}-2|m|}{|m|}\text{, }y=\frac{b}{m}\text{, }z=b\text{, }&\left(b<0\text{ or }m\geq \frac{b}{2}\right)\text{ and }\left(b>0\text{ or }m\leq \frac{b}{2}\right)\text{ and }b\neq 0\text{ and }c=b\text{ and }a=b\\x\in \begin{bmatrix}-3,-1\end{bmatrix}\text{, }y=\sqrt{-\left(x+1\right)\left(x+3\right)}+1\text{, }z=0\text{; }x\in \begin{bmatrix}-3,-1\end{bmatrix}\text{, }y=-\sqrt{-\left(x+1\right)\left(x+3\right)}+1\text{, }z=0\text{, }&a=0\text{ and }m=0\text{ and }b=0\text{ and }c=0\end{matrix}\right.$$