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mode(2%2C4%2C5%2C3%2C2%2C4%2C5%2C6%2C4%2C3%2C2)
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2
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mode(2%2C4%2C5%2C3%2C2%2C4%2C5%2C6%2C4%2C3%2C2)
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https://math.stackexchange.com/questions/470030/proof-involving-chinese-remainder-theorem
Since d\mid a_1-a_2, there is an integer x with xd=a_1-a_2. Since (n_1,n_2)=d, we have ({n_1\over d}, {n_2\over d})=1, so by the chinese remainder theorem, there is an integer k withk\equiv 0\;(\mbox{mod}\;{n_1\over d}) ...
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Masalah Serupa
mode(1,2,3,2,1,2,3)
mode(1,2,3)
mode(20,34,32,35,45,32,45,32,32)
mode(2,4,5,3,2,4,5,6,4,3,2)
mode(10,11,10,12)
mode(1,1,2,2,3,3)
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