Selesaikan y=left(6xright)^2+left(4zright)^2

$$y= { \left(6x \right) }^{ 2 } + { \left(4z \right) }^{ 2 }$$

Cari nilai y

$$y=36x^{2}+16z^{2}$$

Langkah Solusi

Luaskan \left(6x\right)^{2}.

$$y=6^{2}x^{2}+\left(4z\right)^{2}$$

Hitung 6 sampai pangkat 2 dan dapatkan 36.

$$y=36x^{2}+\left(4z\right)^{2}$$

Luaskan \left(4z\right)^{2}.

$$y=36x^{2}+4^{2}z^{2}$$

Hitung 4 sampai pangkat 2 dan dapatkan 16.

$$y=36x^{2}+16z^{2}$$

Cari nilai x (complex solution)

$$x=-\frac{\sqrt{y-16z^{2}}}{6}$$

$$x=\frac{\sqrt{y-16z^{2}}}{6}$$

Cari nilai x

$$x=\frac{\sqrt{y-16z^{2}}}{6}$$

$$x=-\frac{\sqrt{y-16z^{2}}}{6}\text{, }y\geq 16z^{2}$$