Cari nilai y
y=\left(2x-1\right)^{2}
Cari nilai x (complex solution)
x=\frac{-\sqrt{y}+1}{2}
x=\frac{\sqrt{y}+1}{2}
Cari nilai x
x=\frac{-\sqrt{y}+1}{2}
x=\frac{\sqrt{y}+1}{2}\text{, }y\geq 0
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y=4x^{2}-4x+1
Gunakan teorema binomial \left(a-b\right)^{2}=a^{2}-2ab+b^{2} untuk menjabarkan \left(2x-1\right)^{2}.
Contoh
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