Cari nilai B
B=\left(3x-2\right)^{2}
Cari nilai x (complex solution)
x=\frac{-\sqrt{B}+2}{3}
x=\frac{\sqrt{B}+2}{3}
Cari nilai x
x=\frac{-\sqrt{B}+2}{3}
x=\frac{\sqrt{B}+2}{3}\text{, }B\geq 0
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B=9x^{2}-12x+4
Gunakan teorema binomial \left(a-b\right)^{2}=a^{2}-2ab+b^{2} untuk menjabarkan \left(3x-2\right)^{2}.
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