Լուծեք {l}{b^{2}+a^{2}=13}{a^{2}=b^2+c^2}{c^2/a^2=5/4}

$$\left\{ \begin{array} { l } { b ^ { 2 } + a ^ { 2 } = 13 } \\ { a ^ { 2 } = b ^ { 2 } + c ^ { 2 } } \\ { \frac { c ^ { 2 } } { a ^ { 2 } } = \frac { 5 } { 4 } } \end{array} \right.$$

Լուծել b, a, c-ի համար

$$b=\frac{\sqrt{39}i}{3}\approx 2.081665999i\text{, }a=\frac{2\sqrt{39}}{3}\approx 4.163331999\text{, }c=\frac{\sqrt{195}}{3}\approx 4.654746681$$

$$b=\frac{\sqrt{39}i}{3}\approx 2.081665999i\text{, }a=\frac{2\sqrt{39}}{3}\approx 4.163331999\text{, }c=-\frac{\sqrt{195}}{3}\approx -4.654746681$$

$$b=\frac{\sqrt{39}i}{3}\approx 2.081665999i\text{, }a=-\frac{2\sqrt{39}}{3}\approx -4.163331999\text{, }c=\frac{\sqrt{195}}{3}\approx 4.654746681$$

$$b=\frac{\sqrt{39}i}{3}\approx 2.081665999i\text{, }a=-\frac{2\sqrt{39}}{3}\approx -4.163331999\text{, }c=-\frac{\sqrt{195}}{3}\approx -4.654746681$$

$$b=-\frac{\sqrt{39}i}{3}\approx -0-2.081665999i\text{, }a=\frac{2\sqrt{39}}{3}\approx 4.163331999\text{, }c=\frac{\sqrt{195}}{3}\approx 4.654746681$$

$$b=-\frac{\sqrt{39}i}{3}\approx -0-2.081665999i\text{, }a=\frac{2\sqrt{39}}{3}\approx 4.163331999\text{, }c=-\frac{\sqrt{195}}{3}\approx -4.654746681$$

$$b=-\frac{\sqrt{39}i}{3}\approx -0-2.081665999i\text{, }a=-\frac{2\sqrt{39}}{3}\approx -4.163331999\text{, }c=\frac{\sqrt{195}}{3}\approx 4.654746681$$

$$b=-\frac{\sqrt{39}i}{3}\approx -0-2.081665999i\text{, }a=-\frac{2\sqrt{39}}{3}\approx -4.163331999\text{, }c=-\frac{\sqrt{195}}{3}\approx -4.654746681$$