Լուծեք ∫ (from -1 to 3) of x^3+1 wrt x

$$\int_{ -1 }^{ 3 } { x }^{ 3 } +1 d x$$

Գնահատել

$$24$$

Լուծման քայլերը

Evaluate the indefinite integral first.

$$\int x^{3}+1\mathrm{d}x$$

Integrate the sum term by term.

$$\int x^{3}\mathrm{d}x+\int 1\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{3}\mathrm{d}x with \frac{x^{4}}{4}.

$$\frac{x^{4}}{4}+\int 1\mathrm{d}x$$

Find the integral of 1 using the table of common integrals rule \int a\mathrm{d}x=ax.

$$\frac{x^{4}}{4}+x$$

The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.

$$\frac{3^{4}}{4}+3-\left(\frac{\left(-1\right)^{4}}{4}-1\right)$$

Պարզեցնել:

$$24$$