Լուծեք ∫ 12x^2+162x+623 wrt x

$$\int{ 12 { x }^{ 2 } +162x+623 }d x$$

Գնահատել

$$4x^{3}+81x^{2}+623x+С$$

Լուծման քայլերը

Integrate the sum term by term.

$$\int 12x^{2}\mathrm{d}x+\int 162x\mathrm{d}x+\int 623\mathrm{d}x$$

Factor out the constant in each of the terms.

$$12\int x^{2}\mathrm{d}x+162\int x\mathrm{d}x+\int 623\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{2}\mathrm{d}x with \frac{x^{3}}{3}. Բազմապատկեք 12 անգամ \frac{x^{3}}{3}:

$$4x^{3}+162\int x\mathrm{d}x+\int 623\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. Բազմապատկեք 162 անգամ \frac{x^{2}}{2}:

$$4x^{3}+81x^{2}+\int 623\mathrm{d}x$$

Find the integral of 623 using the table of common integrals rule \int a\mathrm{d}x=ax.

$$4x^{3}+81x^{2}+623x$$

If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.

$$4x^{3}+81x^{2}+623x+С$$

Տարբերակել վերագրած x-ը

$$12x^{2}+162x+623$$