Լուծեք ∫ (from 2 to 3) of 5/sqrt{x wrt x

$$\int _ { 2 } ^ { 3 } \frac { 5 } { \sqrt { x } } d x$$

Գնահատել

$$10\left(\sqrt{3}-\sqrt{2}\right)\approx 3.178372452$$

Լուծման քայլերը

Evaluate the indefinite integral first.

$$\int \frac{5}{\sqrt{x}}\mathrm{d}x$$

Factor out the constant using \int af\left(x\right)\mathrm{d}x=a\int f\left(x\right)\mathrm{d}x.

$$5\int \frac{1}{\sqrt{x}}\mathrm{d}x$$

Նորից գրեք \frac{1}{\sqrt{x}}-ը x^{-\frac{1}{2}}-ի տեսքով: Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{-\frac{1}{2}}\mathrm{d}x with \frac{x^{\frac{1}{2}}}{\frac{1}{2}}. Simplify and convert from exponential to radical form.

$$10\sqrt{x}$$

The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.

$$10\times 3^{\frac{1}{2}}-10\times 2^{\frac{1}{2}}$$

Պարզեցնել:

$$10\sqrt{3}-10\sqrt{2}$$