Լուծեք ∫ (from 0 to 1) of (x^2+x+3) wrt y

$$\int _ { 0 } ^ { 1 } ( x ^ { 2 } + x + 3 ) d y$$

Գնահատել

$$x^{2}+x+3$$

Լուծման քայլերը

Evaluate the indefinite integral first.

$$\int x^{2}+x+3\mathrm{d}y$$

Find the integral of x^{2}+x+3 using the table of common integrals rule \int a\mathrm{d}y=ay.

$$\left(x^{2}+x+3\right)y$$

The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.

$$\left(x^{2}+x+3\right)\times 1-\left(x^{2}+x+3\right)\times 0$$

Պարզեցնել:

$$x^{2}+x+3$$

Տարբերակել վերագրած x-ը

$$2x+1$$