Լուծեք ∫ _{-pi/2}^frac{pi{2}}sinx wrt x

$$\int _ { - \frac { \pi } { 2 } } ^ { \frac { \pi } { 2 } } \sin x d x$$

Գնահատել

$$0$$

Լուծման քայլերը

Evaluate the indefinite integral first.

$$\int \sin(x)\mathrm{d}x$$

Use \int \sin(x)\mathrm{d}x=-\cos(x) from the table of common integrals to obtain the result.

$$-\cos(x)$$

The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.

$$-\cos(\frac{1}{2}\pi )+\cos(-\frac{1}{2}\pi )$$

Պարզեցնել:

$$0$$