Riješi 19leq03x+05x+02(60-x-y)leq20

$$19 \leq 03 x + 05 x + 02 ( 60 - x - y ) \leq 20$$

Izračunaj

Koraci rješenja

Pomnožite 0 i 3 da biste dobili 0. Pomnožite 0 i 5 da biste dobili 0. Pomnožite 0 i 2 da biste dobili 0.

$$19\leq 0x+0x+0\left(60-x-y\right)\text{ and }0\times 3x+0\times 5x+0\times 2\left(60-x-y\right)\leq 20$$

Sve puta nula daje nulu.

$$19\leq 0+0x+0\left(60-x-y\right)\text{ and }0\times 3x+0\times 5x+0\times 2\left(60-x-y\right)\leq 20$$

Sve puta nula daje nulu.

$$19\leq 0+0+0\left(60-x-y\right)\text{ and }0\times 3x+0\times 5x+0\times 2\left(60-x-y\right)\leq 20$$

Dodajte 0 broju 0 da biste dobili 0.

$$19\leq 0\left(60-x-y\right)\text{ and }0\times 3x+0\times 5x+0\times 2\left(60-x-y\right)\leq 20$$

Sve puta nula daje nulu.

$$19\leq 0\text{ and }0\times 3x+0\times 5x+0\times 2\left(60-x-y\right)\leq 20$$

Usporedite 19 i 0.

$$\text{false}\text{ and }0\times 3x+0\times 5x+0\times 2\left(60-x-y\right)\leq 20$$

Pomnožite 0 i 3 da biste dobili 0. Pomnožite 0 i 5 da biste dobili 0. Pomnožite 0 i 2 da biste dobili 0.

$$\text{false}\text{ and }0x+0x+0\left(60-x-y\right)\leq 20$$

Sve puta nula daje nulu.

$$\text{false}\text{ and }0+0x+0\left(60-x-y\right)\leq 20$$

Sve puta nula daje nulu.

$$\text{false}\text{ and }0+0+0\left(60-x-y\right)\leq 20$$

Dodajte 0 broju 0 da biste dobili 0.

$$\text{false}\text{ and }0\left(60-x-y\right)\leq 20$$

Sve puta nula daje nulu.

$$\text{false}\text{ and }0\leq 20$$

Usporedite 0 i 20.

$$\text{false}\text{ and }\text{true}$$

Konjunkcija brojeva \text{false} i \text{true} je \text{false}.

$$\text{false}$$