Riješi a^2+b^2=c^2-e^2

$${ a }^{ 2 } + { b }^{ 2 } = { c }^{ 2 } - { e }^{ 2 }$$

Izračunaj a (complex solution)

$$a=-i\sqrt{b^{2}-c^{2}+e^{2}}$$

$$a=i\sqrt{b^{2}-c^{2}+e^{2}}$$

Izračunaj b (complex solution)

$$b=-i\sqrt{a^{2}-c^{2}+e^{2}}$$

$$b=i\sqrt{a^{2}-c^{2}+e^{2}}$$

Izračunaj a

$$a=\sqrt{-b^{2}+c^{2}-e^{2}}$$

$$a=-\sqrt{-b^{2}+c^{2}-e^{2}}\text{, }|c|\geq e\text{ and }|b|\leq \sqrt{\left(c-e\right)\left(c+e\right)}$$

Izračunaj b

$$b=\sqrt{-a^{2}+c^{2}-e^{2}}$$

$$b=-\sqrt{-a^{2}+c^{2}-e^{2}}\text{, }|c|\geq e\text{ and }|a|\leq \sqrt{\left(c-e\right)\left(c+e\right)}$$