Riješi tan^2θ-sec^2θ=

$$\tan ^ { 2 } \theta - \sec ^ { 2 } \theta =$$

Faktor

$$-1$$

Koraci rješenja

Razlika kvadrata može se rastaviti na faktore pomoću pravila: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(\tan(\theta )-\frac{1}{\cos(\theta )}\right)\left(\tan(\theta )+\frac{1}{\cos(\theta )}\right)$$

Razmotrite \tan(\theta )-\frac{1}{\cos(\theta )}. Izlučite \frac{1}{\cos(\theta )}.

$$\frac{\sin(\theta )-1}{\cos(\theta )}$$

Razmotrite \tan(\theta )+\frac{1}{\cos(\theta )}. Izlučite \frac{1}{\cos(\theta )}.

$$\frac{\sin(\theta )+1}{\cos(\theta )}$$

Prepravljanje čitavog izraza rastavljenog na faktore.

$$\left(\sin(\theta )-1\right)\left(\sin(\theta )+1\right)\times \left(\frac{1}{\cos(\theta )}\right)^{2}$$

Izračunaj

$$-1$$