Riješi log_{2}2^x+log_{2}y=3log_{2}2^3x+log_{2}y^2=4

$$\log _ { 2 } 2 ^ { x } + \log _ { 2 } y = 3 \log _ { 2 } 2 ^ { 3 x } + \log _ { 2 } y ^ { 2 } = 4$$

Izračunaj (complex solution)

$$\frac{\ln(2^{x})+\ln(y)}{\ln(2)}=\frac{3\ln(8^{x})+\ln(y^{2})}{\ln(2)}\text{ and }\frac{3\ln(8^{x})+\ln(y^{2})}{\ln(2)}=4$$

Izračunaj x

$$x=-\frac{4}{7}\approx -0,571428571$$

$$y=16\times 2^{\frac{4}{7}}$$

Izračunaj y

$$y=16\times 2^{\frac{4}{7}}$$

$$x = -\frac{4}{7} = -0,5714285714285714$$