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x+2>0 x+2<0
Denominator x+2 cannot be zero since division by zero is not defined. There are two cases.
x>-2
Consider the case when x+2 is positive. Move 2 to the right hand side.
x-4\geq 2\left(x+2\right)
The initial inequality does not change the direction when multiplied by x+2 for x+2>0.
x-4\geq 2x+4
Multiply out the right hand side.
x-2x\geq 4+4
Move the terms containing x to the left hand side and all other terms to the right hand side.
-x\geq 8
Kombinirajte slične izraze.
x\leq -8
Podijelite obje strane sa -1. Budući da je -1 <0, mijenja se smjer nejednadžbe.
x\in \emptyset
Consider condition x>-2 specified above.
x<-2
Now consider the case when x+2 is negative. Move 2 to the right hand side.
x-4\leq 2\left(x+2\right)
The initial inequality changes the direction when multiplied by x+2 for x+2<0.
x-4\leq 2x+4
Multiply out the right hand side.
x-2x\leq 4+4
Move the terms containing x to the left hand side and all other terms to the right hand side.
-x\leq 8
Kombinirajte slične izraze.
x\geq -8
Podijelite obje strane sa -1. Budući da je -1 <0, mijenja se smjer nejednadžbe.
x\in [-8,-2)
Consider condition x<-2 specified above.
x\in [-8,-2)
Konačno je rješenje unija dobivenih rješenja.