Riješi 6626*10^-34^/4*31410^-210^-5

$$\frac{ 6626 \times { 10 }^{ { -34 }^{ } } }{ 4 \cdot 314 { 10 }^{ -2 } { 10 }^{ -5 } }$$

Izračunaj

$$\frac{3313}{628000000000000000000000000000}\approx 5,275477707 \cdot 10^{-27}$$

Koraci rješenja

Da biste pomnožili potencije s istom bazom, zbrojite eksponente. Dodajte -2 i -5 da biste dobili -7.

$$\frac{6626\times 10^{\left(-34\right)^{1}}}{4\times 314\times 10^{-7}}$$

Skratite 2 u brojniku i nazivniku.

$$\frac{3313\times 10^{\left(-34\right)^{1}}}{2\times 314\times 10^{-7}}$$

Izračunajte koliko je 1 na -34 da biste dobili -34.

$$\frac{3313\times 10^{-34}}{2\times 314\times 10^{-7}}$$

Izračunajte koliko je -34 na 10 da biste dobili \frac{1}{10000000000000000000000000000000000}.

$$\frac{3313\times \frac{1}{10000000000000000000000000000000000}}{2\times 314\times 10^{-7}}$$

Pomnožite 3313 i \frac{1}{10000000000000000000000000000000000} da biste dobili \frac{3313}{10000000000000000000000000000000000}.

$$\frac{\frac{3313}{10000000000000000000000000000000000}}{2\times 314\times 10^{-7}}$$

Pomnožite 2 i 314 da biste dobili 628.

$$\frac{\frac{3313}{10000000000000000000000000000000000}}{628\times 10^{-7}}$$

Izračunajte koliko je -7 na 10 da biste dobili \frac{1}{10000000}.

$$\frac{\frac{3313}{10000000000000000000000000000000000}}{628\times \frac{1}{10000000}}$$

Pomnožite 628 i \frac{1}{10000000} da biste dobili \frac{157}{2500000}.

$$\frac{\frac{3313}{10000000000000000000000000000000000}}{\frac{157}{2500000}}$$

Podijelite \frac{3313}{10000000000000000000000000000000000} s \frac{157}{2500000} tako da pomnožite \frac{3313}{10000000000000000000000000000000000} s brojem recipročnim broju \frac{157}{2500000}.

$$\frac{3313}{10000000000000000000000000000000000}\times \frac{2500000}{157}$$

Pomnožite \frac{3313}{10000000000000000000000000000000000} i \frac{2500000}{157} da biste dobili \frac{3313}{628000000000000000000000000000}.

$$\frac{3313}{628000000000000000000000000000}$$

Faktor

$$\frac{3313}{2 ^ {29} \cdot 5 ^ {27} \cdot 157} = 5,275477707006369 \times 10^{-27}$$