Riješi 6-3i/4+2i*(4+2i)/(4+2i)

$$\frac { 6 - 3 i } { 4 + 2 i } \cdot \frac { ( 4 + 2 i ) } { ( 4 + 2 i ) }$$

Izračunaj

$$\frac{9}{10}-\frac{6}{5}i=0,9-1,2i$$

Koraci rješenja

Podijelite 4+2i s 4+2i da biste dobili 1.

$$\frac{6-3i}{4+2i}\times 1$$

Pomnožite brojnik i nazivnik izraza \frac{6-3i}{4+2i} s kompleksnim konjugatom nazivnika, 4-2i.

$$\frac{\left(6-3i\right)\left(4-2i\right)}{\left(4+2i\right)\left(4-2i\right)}\times 1$$

Pomnožite izraz \frac{\left(6-3i\right)\left(4-2i\right)}{\left(4+2i\right)\left(4-2i\right)}.

$$\frac{18-24i}{20}\times 1$$

Podijelite 18-24i s 20 da biste dobili \frac{9}{10}-\frac{6}{5}i.

$$\left(\frac{9}{10}-\frac{6}{5}i\right)\times 1$$

Pomnožite \frac{9}{10}-\frac{6}{5}i i 1 da biste dobili \frac{9}{10}-\frac{6}{5}i.

$$\frac{9}{10}-\frac{6}{5}i$$

Realni dio

$$\frac{9}{10} = 0,9$$

Koraci rješenja

Podijelite 4+2i s 4+2i da biste dobili 1.

$$Re(\frac{6-3i}{4+2i}\times 1)$$

Pomnožite brojnik i nazivnik izraza \frac{6-3i}{4+2i} s kompleksnim konjugatom nazivnika, 4-2i.

$$Re(\frac{\left(6-3i\right)\left(4-2i\right)}{\left(4+2i\right)\left(4-2i\right)}\times 1)$$

Pomnožite izraz \frac{\left(6-3i\right)\left(4-2i\right)}{\left(4+2i\right)\left(4-2i\right)}.

$$Re(\frac{18-24i}{20}\times 1)$$

Podijelite 18-24i s 20 da biste dobili \frac{9}{10}-\frac{6}{5}i.

$$Re(\left(\frac{9}{10}-\frac{6}{5}i\right)\times 1)$$

Pomnožite \frac{9}{10}-\frac{6}{5}i i 1 da biste dobili \frac{9}{10}-\frac{6}{5}i.

$$Re(\frac{9}{10}-\frac{6}{5}i)$$

Realni dio broja \frac{9}{10}-\frac{6}{5}i jest \frac{9}{10}.

$$\frac{9}{10}$$