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y=x^{3}-36x^{2}+432x-1728-10
Usar teorema binomial \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} para expandir \left(x-12\right)^{3}.
y=x^{3}-36x^{2}+432x-1738
Resta 10 de -1728 para obter -1738.