Resolver f(11/2)=(11/2)-1/2(1frac{1{2})^2-(11/2)^2}=

$$f ( 1 \frac { 1 } { 2 } ) = \frac { ( 1 \frac { 1 } { 2 } ) - 1 } { 2 ( 1 \frac { 1 } { 2 } ) ^ { 2 } - ( 1 \frac { 1 } { 2 } ) ^ { 2 } } =$$

Calcular

$$\frac{2}{9}\approx 0.222222222$$

Pasos da solución

Multiplica 1 e 2 para obter 2.

$$\frac{\frac{2+1}{2}-1}{2\times \left(\frac{1\times 2+1}{2}\right)^{2}-\left(\frac{1\times 2+1}{2}\right)^{2}}$$

Suma 2 e 1 para obter 3.

$$\frac{\frac{3}{2}-1}{2\times \left(\frac{1\times 2+1}{2}\right)^{2}-\left(\frac{1\times 2+1}{2}\right)^{2}}$$

Resta 1 de \frac{3}{2} para obter \frac{1}{2}.

$$\frac{\frac{1}{2}}{2\times \left(\frac{1\times 2+1}{2}\right)^{2}-\left(\frac{1\times 2+1}{2}\right)^{2}}$$

Multiplica 1 e 2 para obter 2.

$$\frac{\frac{1}{2}}{2\times \left(\frac{2+1}{2}\right)^{2}-\left(\frac{1\times 2+1}{2}\right)^{2}}$$

Suma 2 e 1 para obter 3.

$$\frac{\frac{1}{2}}{2\times \left(\frac{3}{2}\right)^{2}-\left(\frac{1\times 2+1}{2}\right)^{2}}$$

Calcula \frac{3}{2} á potencia de 2 e obtén \frac{9}{4}.

$$\frac{\frac{1}{2}}{2\times \frac{9}{4}-\left(\frac{1\times 2+1}{2}\right)^{2}}$$

Multiplica 2 e \frac{9}{4} para obter \frac{9}{2}.

$$\frac{\frac{1}{2}}{\frac{9}{2}-\left(\frac{1\times 2+1}{2}\right)^{2}}$$

Multiplica 1 e 2 para obter 2.

$$\frac{\frac{1}{2}}{\frac{9}{2}-\left(\frac{2+1}{2}\right)^{2}}$$

Suma 2 e 1 para obter 3.

$$\frac{\frac{1}{2}}{\frac{9}{2}-\left(\frac{3}{2}\right)^{2}}$$

Calcula \frac{3}{2} á potencia de 2 e obtén \frac{9}{4}.

$$\frac{\frac{1}{2}}{\frac{9}{2}-\frac{9}{4}}$$

Resta \frac{9}{4} de \frac{9}{2} para obter \frac{9}{4}.

$$\frac{\frac{1}{2}}{\frac{9}{4}}$$

Divide \frac{1}{2} entre \frac{9}{4} mediante a multiplicación de \frac{1}{2} polo recíproco de \frac{9}{4}.

$$\frac{1}{2}\times \frac{4}{9}$$

Multiplica \frac{1}{2} e \frac{4}{9} para obter \frac{2}{9}.

$$\frac{2}{9}$$

Factorizar

$$\frac{2}{3 ^ {2}} = 0.2222222222222222$$