Resolver BS=(0.04-x)^2/(0.05-x)^2

$$B S = \frac { ( 0.04 - x ) ^ { 2 } } { ( 0.05 - x ) ^ { 2 } }$$

Resolver B

$$\left\{\begin{matrix}B=\frac{16\times \left(\frac{25x-1}{20x-1}\right)^{2}}{25S}\text{, }&x\neq \frac{1}{20}\text{ and }S\neq 0\\B\in \mathrm{R}\text{, }&S=0\text{ and }x=\frac{1}{25}\end{matrix}\right.$$

Pasos para resolver unha ecuación lineal

Usar teorema binomial \left(a-b\right)^{2}=a^{2}-2ab+b^{2} para expandir \left(0.04-x\right)^{2}.

$$BS=\frac{0.0016-0.08x+x^{2}}{\left(0.05-x\right)^{2}}$$

Usar teorema binomial \left(a-b\right)^{2}=a^{2}-2ab+b^{2} para expandir \left(0.05-x\right)^{2}.

$$BS=\frac{0.0016-0.08x+x^{2}}{0.0025-0.1x+x^{2}}$$

A ecuación está en forma estándar.

$$SB=\frac{x^{2}-\frac{2x}{25}+0.0016}{x^{2}-\frac{x}{10}+0.0025}$$

Divide ambos lados entre S.

$$\frac{SB}{S}=\frac{16\left(25x-1\right)^{2}}{25\left(20x-1\right)^{2}S}$$

A división entre S desfai a multiplicación por S.

$$B=\frac{16\left(25x-1\right)^{2}}{25\left(20x-1\right)^{2}S}$$

Divide \frac{16\left(25x-1\right)^{2}}{25\left(20x-1\right)^{2}} entre S.

$$B=\frac{16\left(25x-1\right)^{2}}{25S\left(20x-1\right)^{2}}$$

Resolver S

$$\left\{\begin{matrix}S=\frac{16\times \left(\frac{25x-1}{20x-1}\right)^{2}}{25B}\text{, }&x\neq \frac{1}{20}\text{ and }B\neq 0\\S\in \mathrm{R}\text{, }&B=0\text{ and }x=\frac{1}{25}\end{matrix}\right.$$

Pasos para resolver unha ecuación lineal

Usar teorema binomial \left(a-b\right)^{2}=a^{2}-2ab+b^{2} para expandir \left(0.04-x\right)^{2}.

$$BS=\frac{0.0016-0.08x+x^{2}}{\left(0.05-x\right)^{2}}$$

Usar teorema binomial \left(a-b\right)^{2}=a^{2}-2ab+b^{2} para expandir \left(0.05-x\right)^{2}.

$$BS=\frac{0.0016-0.08x+x^{2}}{0.0025-0.1x+x^{2}}$$

A ecuación está en forma estándar.

$$BS=\frac{x^{2}-\frac{2x}{25}+0.0016}{x^{2}-\frac{x}{10}+0.0025}$$

Divide ambos lados entre B.

$$\frac{BS}{B}=\frac{16\left(25x-1\right)^{2}}{25\left(20x-1\right)^{2}B}$$

A división entre B desfai a multiplicación por B.

$$S=\frac{16\left(25x-1\right)^{2}}{25\left(20x-1\right)^{2}B}$$

Divide \frac{16\left(25x-1\right)^{2}}{25\left(20x-1\right)^{2}} entre B.

$$S=\frac{16\left(25x-1\right)^{2}}{25B\left(20x-1\right)^{2}}$$