Resolver 7^2[(2-3)+6]-64^13{6+[3+2(4+2)^2-1](-1)}

$$7 ^ { 2 } [ ( 2 - 3 ) + 6 ] - 64 ^ { 13 } \{ 6 + [ 3 + 2 ( 4 + 2 ) ^ { 2 } - 1 ] ( - 1 ) \}$$

Calcular

$$20551738933448695970005237$$

Pasos da solución

Calcula 7 á potencia de 2 e obtén 49.

$$49\left(2-3+6\right)-64^{13}\left(6+\left(3+2\left(4+2\right)^{2}-1\right)\left(-1\right)\right)$$

Resta 3 de 2 para obter -1.

$$49\left(-1+6\right)-64^{13}\left(6+\left(3+2\left(4+2\right)^{2}-1\right)\left(-1\right)\right)$$

Suma -1 e 6 para obter 5.

$$49\times 5-64^{13}\left(6+\left(3+2\left(4+2\right)^{2}-1\right)\left(-1\right)\right)$$

Multiplica 49 e 5 para obter 245.

$$245-64^{13}\left(6+\left(3+2\left(4+2\right)^{2}-1\right)\left(-1\right)\right)$$

Calcula 64 á potencia de 13 e obtén 302231454903657293676544.

$$245-302231454903657293676544\left(6+\left(3+2\left(4+2\right)^{2}-1\right)\left(-1\right)\right)$$

Suma 4 e 2 para obter 6.

$$245-302231454903657293676544\left(6+\left(3+2\times 6^{2}-1\right)\left(-1\right)\right)$$

Calcula 6 á potencia de 2 e obtén 36.

$$245-302231454903657293676544\left(6+\left(3+2\times 36-1\right)\left(-1\right)\right)$$

Multiplica 2 e 36 para obter 72.

$$245-302231454903657293676544\left(6+\left(3+72-1\right)\left(-1\right)\right)$$

Suma 3 e 72 para obter 75.

$$245-302231454903657293676544\left(6+\left(75-1\right)\left(-1\right)\right)$$

Resta 1 de 75 para obter 74.

$$245-302231454903657293676544\left(6+74\left(-1\right)\right)$$

Multiplica 74 e -1 para obter -74.

$$245-302231454903657293676544\left(6-74\right)$$

Resta 74 de 6 para obter -68.

$$245-302231454903657293676544\left(-68\right)$$

Multiplica 302231454903657293676544 e -68 para obter -20551738933448695970004992.

$$245-\left(-20551738933448695970004992\right)$$

O contrario de -20551738933448695970004992 é 20551738933448695970004992.

$$245+20551738933448695970004992$$

Suma 245 e 20551738933448695970004992 para obter 20551738933448695970005237.

$$20551738933448695970005237$$

Factorizar

$$127\times 16657\times 9715117728967224283$$