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2\left(27a^{3}+b^{3}\right)
Factoriza 2.
\left(3a+b\right)\left(9a^{2}-3ab+b^{2}\right)
Considera 27a^{3}+b^{3}. Pódese factorizar a suma dos cubos usando a regra: p^{3}+q^{3}=\left(p+q\right)\left(p^{2}-pq+q^{2}\right).
2\left(3a+b\right)\left(9a^{2}-3ab+b^{2}\right)
Reescribe a expresión factorizada completa.