Resolver 47*16*10^-19=667*10^-34*A

$$47 \times 16 \times 10 ^ { - 19 } = 667 \times 10 ^ { - 34 } \times A$$

Resolver A

$$A=\frac{752000000000000000}{667}\approx 1.127436282 \cdot 10^{15}$$

Pasos para resolver unha ecuación lineal

Multiplica 47 e 16 para obter 752.

$$752\times 10^{-19}=667\times 10^{-34}A$$

Calcula 10 á potencia de -19 e obtén \frac{1}{10000000000000000000}.

$$752\times \frac{1}{10000000000000000000}=667\times 10^{-34}A$$

Multiplica 752 e \frac{1}{10000000000000000000} para obter \frac{47}{625000000000000000}.

$$\frac{47}{625000000000000000}=667\times 10^{-34}A$$

Calcula 10 á potencia de -34 e obtén \frac{1}{10000000000000000000000000000000000}.

$$\frac{47}{625000000000000000}=667\times \frac{1}{10000000000000000000000000000000000}A$$

Multiplica 667 e \frac{1}{10000000000000000000000000000000000} para obter \frac{667}{10000000000000000000000000000000000}.

$$\frac{47}{625000000000000000}=\frac{667}{10000000000000000000000000000000000}A$$

Cambia de lado para que todos os termos variables estean no lado esquerdo.

$$\frac{667}{10000000000000000000000000000000000}A=\frac{47}{625000000000000000}$$

Multiplica ambos lados por \frac{10000000000000000000000000000000000}{667}, o recíproco de \frac{667}{10000000000000000000000000000000000}.

$$A=\frac{47}{625000000000000000}\times \frac{10000000000000000000000000000000000}{667}$$

Multiplica \frac{47}{625000000000000000} e \frac{10000000000000000000000000000000000}{667} para obter \frac{752000000000000000}{667}.

$$A=\frac{752000000000000000}{667}$$