Resolver 4.7*1.610^-19=6.67*10^-34*A

$$4.7 \cdot 1.6 { 10 }^{ -19 } = 6.67 \times { 10 }^{ -34 } \times A$$

Resolver A

$$A=\frac{752000000000000000}{667}\approx 1.127436282 \cdot 10^{15}$$

Pasos para resolver unha ecuación lineal

Multiplica 4.7 e 1.6 para obter 7.52.

$$7.52\times 10^{-19}=6.67\times 10^{-34}A$$

Calcula 10 á potencia de -19 e obtén \frac{1}{10000000000000000000}.

$$7.52\times \frac{1}{10000000000000000000}=6.67\times 10^{-34}A$$

Multiplica 7.52 e \frac{1}{10000000000000000000} para obter \frac{47}{62500000000000000000}.

$$\frac{47}{62500000000000000000}=6.67\times 10^{-34}A$$

Calcula 10 á potencia de -34 e obtén \frac{1}{10000000000000000000000000000000000}.

$$\frac{47}{62500000000000000000}=6.67\times \frac{1}{10000000000000000000000000000000000}A$$

Multiplica 6.67 e \frac{1}{10000000000000000000000000000000000} para obter \frac{667}{1000000000000000000000000000000000000}.

$$\frac{47}{62500000000000000000}=\frac{667}{1000000000000000000000000000000000000}A$$

Cambia de lado para que todos os termos variables estean no lado esquerdo.

$$\frac{667}{1000000000000000000000000000000000000}A=\frac{47}{62500000000000000000}$$

Multiplica ambos lados por \frac{1000000000000000000000000000000000000}{667}, o recíproco de \frac{667}{1000000000000000000000000000000000000}.

$$A=\frac{47}{62500000000000000000}\times \frac{1000000000000000000000000000000000000}{667}$$

Multiplica \frac{47}{62500000000000000000} e \frac{1000000000000000000000000000000000000}{667} para obter \frac{752000000000000000}{667}.

$$A=\frac{752000000000000000}{667}$$