Resolver 32/5y+11/4=71/3

$$3 \frac { 2 } { 5 } y + 1 \frac { 1 } { 4 } = 7 \frac { 1 } { 3 }$$

Resolver y

$$y = \frac{365}{204} = 1\frac{161}{204} \approx 1.789215686$$

Pasos para resolver unha ecuación lineal

Multiplica ambos lados da ecuación por 60, o mínimo común denominador de 5,4,3.

$$12\left(3\times 5+2\right)y+15\left(1\times 4+1\right)=20\left(7\times 3+1\right)$$

Multiplica 3 e 5 para obter 15.

$$12\left(15+2\right)y+15\left(1\times 4+1\right)=20\left(7\times 3+1\right)$$

Suma 15 e 2 para obter 17.

$$12\times 17y+15\left(1\times 4+1\right)=20\left(7\times 3+1\right)$$

Multiplica 12 e 17 para obter 204.

$$204y+15\left(1\times 4+1\right)=20\left(7\times 3+1\right)$$

Multiplica 1 e 4 para obter 4.

$$204y+15\left(4+1\right)=20\left(7\times 3+1\right)$$

Suma 4 e 1 para obter 5.

$$204y+15\times 5=20\left(7\times 3+1\right)$$

Multiplica 15 e 5 para obter 75.

$$204y+75=20\left(7\times 3+1\right)$$

Multiplica 7 e 3 para obter 21.

$$204y+75=20\left(21+1\right)$$

Suma 21 e 1 para obter 22.

$$204y+75=20\times 22$$

Multiplica 20 e 22 para obter 440.

$$204y+75=440$$

Resta 75 en ambos lados.

$$204y=440-75$$

Resta 75 de 440 para obter 365.

$$204y=365$$

Divide ambos lados entre 204.

$$y=\frac{365}{204}$$