Resolver 11x=9x/5y+13y

$$11x= \frac{ 9x }{ 5y } +13y$$

Resolver x

$$x=\frac{65y^{2}}{55y-9}$$

$$y\neq \frac{9}{55}\text{ and }y\neq 0$$

Pasos para resolver unha ecuación lineal

Multiplica ambos lados da ecuación por 5y.

$$11x\times 5y=9x+13y\times 5y$$

Multiplica 11 e 5 para obter 55.

$$55xy=9x+13y\times 5y$$

Multiplica y e y para obter y^{2}.

$$55xy=9x+13y^{2}\times 5$$

Multiplica 13 e 5 para obter 65.

$$55xy=9x+65y^{2}$$

Resta 9x en ambos lados.

$$55xy-9x=65y^{2}$$

Combina todos os termos que conteñan x.

$$\left(55y-9\right)x=65y^{2}$$

Divide ambos lados entre 55y-9.

$$\frac{\left(55y-9\right)x}{55y-9}=\frac{65y^{2}}{55y-9}$$

A división entre 55y-9 desfai a multiplicación por 55y-9.

$$x=\frac{65y^{2}}{55y-9}$$

Resolver y (complex solution)

$$y=-\frac{\sqrt{3025x^{2}-2340x}}{130}+\frac{11x}{26}$$

$$y=\frac{\sqrt{3025x^{2}-2340x}}{130}+\frac{11x}{26}\text{, }x\neq 0$$

Resolver y

$$y=-\frac{\sqrt{3025x^{2}-2340x}}{130}+\frac{11x}{26}$$

$$y=\frac{\sqrt{3025x^{2}-2340x}}{130}+\frac{11x}{26}\text{, }x\geq \frac{468}{605}\text{ or }x<0$$