Resolver 10^-1:2^-5*5^-1

$$10 ^ { - 1 } : 2 ^ { - 5 } \cdot 5 ^ { - 1 }$$

Calcular

$$\frac{16}{25}=0.64$$

Pasos da solución

Calcula 10 á potencia de -1 e obtén \frac{1}{10}.

$$\frac{\frac{1}{10}}{2^{-5}}\times 5^{-1}$$

Calcula 2 á potencia de -5 e obtén \frac{1}{32}.

$$\frac{\frac{1}{10}}{\frac{1}{32}}\times 5^{-1}$$

Divide \frac{1}{10} entre \frac{1}{32} mediante a multiplicación de \frac{1}{10} polo recíproco de \frac{1}{32}.

$$\frac{1}{10}\times 32\times 5^{-1}$$

Multiplica \frac{1}{10} e 32 para obter \frac{16}{5}.

$$\frac{16}{5}\times 5^{-1}$$

Calcula 5 á potencia de -1 e obtén \frac{1}{5}.

$$\frac{16}{5}\times \frac{1}{5}$$

Multiplica \frac{16}{5} e \frac{1}{5} para obter \frac{16}{25}.

$$\frac{16}{25}$$

Factorizar

$$\frac{2 ^ {4}}{5 ^ {2}} = 0.64$$