Resolver 10^-1+(-0.3)^0:11/10

$$10 ^ { - 1 } + ( - 0.3 ) ^ { 0 } : 1 \frac { 1 } { 10 }$$

Calcular

$$\frac{111}{110}\approx 1.009090909$$

Pasos da solución

Calcula 10 á potencia de -1 e obtén \frac{1}{10}.

$$\frac{1}{10}+\frac{\left(-0.3\right)^{0}}{\frac{1\times 10+1}{10}}$$

Calcula -0.3 á potencia de 0 e obtén 1.

$$\frac{1}{10}+\frac{1}{\frac{1\times 10+1}{10}}$$

Multiplica 1 e 10 para obter 10.

$$\frac{1}{10}+\frac{1}{\frac{10+1}{10}}$$

Suma 10 e 1 para obter 11.

$$\frac{1}{10}+\frac{1}{\frac{11}{10}}$$

Divide 1 entre \frac{11}{10} mediante a multiplicación de 1 polo recíproco de \frac{11}{10}.

$$\frac{1}{10}+1\times \frac{10}{11}$$

Multiplica 1 e \frac{10}{11} para obter \frac{10}{11}.

$$\frac{1}{10}+\frac{10}{11}$$

Suma \frac{1}{10} e \frac{10}{11} para obter \frac{111}{110}.

$$\frac{111}{110}$$

Factorizar

$$\frac{3 \cdot 37}{2 \cdot 5 \cdot 11} = 1\frac{1}{110} = 1.009090909090909$$