Resolver 1+2^3(4*4/2)^2div35=

$$1 + 2 ^ { 3 } ( 4 \times \frac { 4 } { 2 } ) ^ { 2 } \div 35 =$$

Calcular

$$\frac{547}{35}\approx 15.628571429$$

Pasos da solución

Calcula 2 á potencia de 3 e obtén 8.

$$1+\frac{8\times \left(4\times \frac{4}{2}\right)^{2}}{35}$$

Divide 4 entre 2 para obter 2.

$$1+\frac{8\times \left(4\times 2\right)^{2}}{35}$$

Multiplica 4 e 2 para obter 8.

$$1+\frac{8\times 8^{2}}{35}$$

Calcula 8 á potencia de 2 e obtén 64.

$$1+\frac{8\times 64}{35}$$

Multiplica 8 e 64 para obter 512.

$$1+\frac{512}{35}$$

Suma 1 e \frac{512}{35} para obter \frac{547}{35}.

$$\frac{547}{35}$$

Factorizar

$$\frac{547}{5 \cdot 7} = 15\frac{22}{35} = 15.628571428571428$$