Resolver -3^2+(-025)^100*4^100+(1/2-1/3)*(1/6)^-2

$$- 3 ^ { 2 } + ( - 025 ) ^ { 100 } \times 4 ^ { 100 } + ( \frac { 1 } { 2 } - \frac { 1 } { 3 } ) \times ( \frac { 1 } { 6 } ) ^ { - 2 }$$

Calcular

$$-3$$

Pasos da solución

Calcula 3 á potencia de 2 e obtén 9.

$$-9+\left(0\times 25\right)^{100}\times 4^{100}+\left(\frac{1}{2}-\frac{1}{3}\right)\times \left(\frac{1}{6}\right)^{-2}$$

Multiplica 0 e 25 para obter 0.

$$-9+0^{100}\times 4^{100}+\left(\frac{1}{2}-\frac{1}{3}\right)\times \left(\frac{1}{6}\right)^{-2}$$

Calcula 0 á potencia de 100 e obtén 0.

$$-9+0\times 4^{100}+\left(\frac{1}{2}-\frac{1}{3}\right)\times \left(\frac{1}{6}\right)^{-2}$$

Calcula 4 á potencia de 100 e obtén 1606938044258990275541962092341162602522202993782792835301376.

$$-9+0\times 1606938044258990275541962092341162602522202993782792835301376+\left(\frac{1}{2}-\frac{1}{3}\right)\times \left(\frac{1}{6}\right)^{-2}$$

Multiplica 0 e 1606938044258990275541962092341162602522202993782792835301376 para obter 0.

$$-9+0+\left(\frac{1}{2}-\frac{1}{3}\right)\times \left(\frac{1}{6}\right)^{-2}$$

Suma -9 e 0 para obter -9.

$$-9+\left(\frac{1}{2}-\frac{1}{3}\right)\times \left(\frac{1}{6}\right)^{-2}$$

Resta \frac{1}{3} de \frac{1}{2} para obter \frac{1}{6}.

$$-9+\frac{1}{6}\times \left(\frac{1}{6}\right)^{-2}$$

Calcula \frac{1}{6} á potencia de -2 e obtén 36.

$$-9+\frac{1}{6}\times 36$$

Multiplica \frac{1}{6} e 36 para obter 6.

$$-9+6$$

Suma -9 e 6 para obter -3.

$$-3$$

Factorizar

$$-3$$