Resolver -2^3+1/3*(2017+3)^0-(1/3)^-2

$$- 2 ^ { 3 } + \frac { 1 } { 3 } \times ( 2017 + 3 ) ^ { 0 } - ( \frac { 1 } { 3 } ) ^ { - 2 }$$

Calcular

$$-\frac{50}{3}\approx -16.666666667$$

Pasos da solución

Calcula 2 á potencia de 3 e obtén 8.

$$-8+\frac{1}{3}\left(2017+3\right)^{0}-\left(\frac{1}{3}\right)^{-2}$$

Suma 2017 e 3 para obter 2020.

$$-8+\frac{1}{3}\times 2020^{0}-\left(\frac{1}{3}\right)^{-2}$$

Calcula 2020 á potencia de 0 e obtén 1.

$$-8+\frac{1}{3}\times 1-\left(\frac{1}{3}\right)^{-2}$$

Multiplica \frac{1}{3} e 1 para obter \frac{1}{3}.

$$-8+\frac{1}{3}-\left(\frac{1}{3}\right)^{-2}$$

Suma -8 e \frac{1}{3} para obter -\frac{23}{3}.

$$-\frac{23}{3}-\left(\frac{1}{3}\right)^{-2}$$

Calcula \frac{1}{3} á potencia de -2 e obtén 9.

$$-\frac{23}{3}-9$$

Resta 9 de -\frac{23}{3} para obter -\frac{50}{3}.

$$-\frac{50}{3}$$

Factorizar

$$-\frac{50}{3} = -16\frac{2}{3} = -16.666666666666668$$