Resolver -11/2-3/4:(11/2-1/3)^2=

$$- 1 \frac { 1 } { 2 } - \frac { 3 } { 4 } : ( 1 \frac { 1 } { 2 } - \frac { 1 } { 3 } ) ^ { 2 } =$$

Calcular

$$-\frac{201}{98}\approx -2.051020408$$

Pasos da solución

Multiplica 1 e 2 para obter 2.

$$-\frac{2+1}{2}-\frac{\frac{3}{4}}{\left(\frac{1\times 2+1}{2}-\frac{1}{3}\right)^{2}}$$

Suma 2 e 1 para obter 3.

$$-\frac{3}{2}-\frac{\frac{3}{4}}{\left(\frac{1\times 2+1}{2}-\frac{1}{3}\right)^{2}}$$

Multiplica 1 e 2 para obter 2.

$$-\frac{3}{2}-\frac{\frac{3}{4}}{\left(\frac{2+1}{2}-\frac{1}{3}\right)^{2}}$$

Suma 2 e 1 para obter 3.

$$-\frac{3}{2}-\frac{\frac{3}{4}}{\left(\frac{3}{2}-\frac{1}{3}\right)^{2}}$$

Resta \frac{1}{3} de \frac{3}{2} para obter \frac{7}{6}.

$$-\frac{3}{2}-\frac{\frac{3}{4}}{\left(\frac{7}{6}\right)^{2}}$$

Calcula \frac{7}{6} á potencia de 2 e obtén \frac{49}{36}.

$$-\frac{3}{2}-\frac{\frac{3}{4}}{\frac{49}{36}}$$

Divide \frac{3}{4} entre \frac{49}{36} mediante a multiplicación de \frac{3}{4} polo recíproco de \frac{49}{36}.

$$-\frac{3}{2}-\frac{3}{4}\times \frac{36}{49}$$

Multiplica \frac{3}{4} e \frac{36}{49} para obter \frac{27}{49}.

$$-\frac{3}{2}-\frac{27}{49}$$

Resta \frac{27}{49} de -\frac{3}{2} para obter -\frac{201}{98}.

$$-\frac{201}{98}$$

Factorizar

$$-\frac{201}{98} = -2\frac{5}{98} = -2.0510204081632653$$