Resolver -(1/3+frac{7/9)^{2}}{(1-1/2)^{2}*(-2)^3-3/2}+[-(-frac{1}{6})^2+frac{frac{1}{4}-frac{1}{5}}{(1-frac{2}{5})^2}]^2-frac{frac{1}{3}-frac{2}{9}}{frac{1}{8}-frac{15}{8}}=

$$- \frac { ( \frac { 1 } { 3 } + \frac { 7 } { 9 } ) ^ { 2 } } { ( 1 - \frac { 1 } { 2 } ) ^ { 2 } \cdot ( - 2 ) ^ { 3 } - \frac { 3 } { 2 } } + [ - ( - \frac { 1 } { 6 } ) ^ { 2 } + \frac { \frac { 1 } { 4 } - \frac { 1 } { 5 } } { ( 1 - \frac { 2 } { 5 } ) ^ { 2 } } ] ^ { 2 } - \frac { \frac { 1 } { 3 } - \frac { 2 } { 9 } } { \frac { 1 } { 8 } - \frac { 15 } { 8 } } =$$

Calcular

$$\frac{3}{7}\approx 0.428571429$$

Pasos da solución

Suma \frac{1}{3} e \frac{7}{9} para obter \frac{10}{9}.

$$-\frac{\left(\frac{10}{9}\right)^{2}}{\left(1-\frac{1}{2}\right)^{2}\left(-2\right)^{3}-\frac{3}{2}}+\left(-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}$$

Calcula \frac{10}{9} á potencia de 2 e obtén \frac{100}{81}.

$$-\frac{\frac{100}{81}}{\left(1-\frac{1}{2}\right)^{2}\left(-2\right)^{3}-\frac{3}{2}}+\left(-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}$$

Resta \frac{1}{2} de 1 para obter \frac{1}{2}.

$$-\frac{\frac{100}{81}}{\left(\frac{1}{2}\right)^{2}\left(-2\right)^{3}-\frac{3}{2}}+\left(-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}$$

Calcula \frac{1}{2} á potencia de 2 e obtén \frac{1}{4}.

$$-\frac{\frac{100}{81}}{\frac{1}{4}\left(-2\right)^{3}-\frac{3}{2}}+\left(-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}$$

Calcula -2 á potencia de 3 e obtén -8.

$$-\frac{\frac{100}{81}}{\frac{1}{4}\left(-8\right)-\frac{3}{2}}+\left(-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}$$

Multiplica \frac{1}{4} e -8 para obter -2.

$$-\frac{\frac{100}{81}}{-2-\frac{3}{2}}+\left(-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}$$

Resta \frac{3}{2} de -2 para obter -\frac{7}{2}.

$$-\frac{\frac{100}{81}}{-\frac{7}{2}}+\left(-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}$$

Divide \frac{100}{81} entre -\frac{7}{2} mediante a multiplicación de \frac{100}{81} polo recíproco de -\frac{7}{2}.

$$-\frac{100}{81}\left(-\frac{2}{7}\right)+\left(-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}$$

Multiplica \frac{100}{81} e -\frac{2}{7} para obter -\frac{200}{567}.

$$-\left(-\frac{200}{567}\right)+\left(-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}$$

O contrario de -\frac{200}{567} é \frac{200}{567}.

$$\frac{200}{567}+\left(-\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}$$

Calcula -\frac{1}{6} á potencia de 2 e obtén \frac{1}{36}.

$$\frac{200}{567}+\left(-\frac{1}{36}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}$$

Resta \frac{1}{5} de \frac{1}{4} para obter \frac{1}{20}.

$$\frac{200}{567}+\left(-\frac{1}{36}+\frac{\frac{1}{20}}{\left(1-\frac{2}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}$$

Resta \frac{2}{5} de 1 para obter \frac{3}{5}.

$$\frac{200}{567}+\left(-\frac{1}{36}+\frac{\frac{1}{20}}{\left(\frac{3}{5}\right)^{2}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}$$

Calcula \frac{3}{5} á potencia de 2 e obtén \frac{9}{25}.

$$\frac{200}{567}+\left(-\frac{1}{36}+\frac{\frac{1}{20}}{\frac{9}{25}}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}$$

Divide \frac{1}{20} entre \frac{9}{25} mediante a multiplicación de \frac{1}{20} polo recíproco de \frac{9}{25}.

$$\frac{200}{567}+\left(-\frac{1}{36}+\frac{1}{20}\times \frac{25}{9}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}$$

Multiplica \frac{1}{20} e \frac{25}{9} para obter \frac{5}{36}.

$$\frac{200}{567}+\left(-\frac{1}{36}+\frac{5}{36}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}$$

Suma -\frac{1}{36} e \frac{5}{36} para obter \frac{1}{9}.

$$\frac{200}{567}+\left(\frac{1}{9}\right)^{2}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}$$

Calcula \frac{1}{9} á potencia de 2 e obtén \frac{1}{81}.

$$\frac{200}{567}+\frac{1}{81}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}$$

Suma \frac{200}{567} e \frac{1}{81} para obter \frac{23}{63}.

$$\frac{23}{63}-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}$$

Resta \frac{2}{9} de \frac{1}{3} para obter \frac{1}{9}.

$$\frac{23}{63}-\frac{\frac{1}{9}}{\frac{1}{8}-\frac{15}{8}}$$

Resta \frac{15}{8} de \frac{1}{8} para obter -\frac{7}{4}.

$$\frac{23}{63}-\frac{\frac{1}{9}}{-\frac{7}{4}}$$

Divide \frac{1}{9} entre -\frac{7}{4} mediante a multiplicación de \frac{1}{9} polo recíproco de -\frac{7}{4}.

$$\frac{23}{63}-\frac{1}{9}\left(-\frac{4}{7}\right)$$

Multiplica \frac{1}{9} e -\frac{4}{7} para obter -\frac{4}{63}.

$$\frac{23}{63}-\left(-\frac{4}{63}\right)$$

O contrario de -\frac{4}{63} é \frac{4}{63}.

$$\frac{23}{63}+\frac{4}{63}$$

Suma \frac{23}{63} e \frac{4}{63} para obter \frac{3}{7}.

$$\frac{3}{7}$$

Factorizar

$$\frac{3}{7} = 0.42857142857142855$$